MATH SOLVE

5 months ago

Q:
# A is the midpoint of JM . If JA = 6x - 4 and JM = 9x + 13, find AM.The length of AM is

Accepted Solution

A:

Answer:AM = 38Step-by-step explanation:Since A is the midpoint of JM, thenJA = AM = 6x - 4 , andJA + AM = JM ← substitute values6x - 4 + 6x - 4 = 9x + 13, that is12x - 8 = 9x + 13 ( subtract 9x from both sides )3x - 8 = 13 ( add 8 to both sides )3x = 21 ( divide both sides by 3 )x = 7HenceAM = 6x - 4 = (6 × 7) - 4 = 42 - 4 = 38