If a polynomial function f(x) has roots 6 and square root of 5, what must also be a root of f(x)?A. -6B. Square root of -5C. 6 - Square root of 5D. 6 + Square root of 5

Answer:-[tex]\sqrt{5}[/tex]Step-by-step explanation:A root with square root or under root is only obtained when we take the square root of both sides. Remember that when we take a square root, there are two possible answers:One answer with positive square rootOne answer with negative square rootFor example, for the equation:[tex]x^{2}=3[/tex]If we take the square root of both sides, the answers will be:[tex]x=\sqrt{3} \text{ or } x= -\sqrt{3}[/tex]Only getting one solution with square root is not possible. Solutions with square root always occur in pairs.For given case, the roots are 6 and [tex]\sqrt{5}[/tex]. Therefore, the 3rd root of the polynomial function f(x) had to be -[tex]\sqrt{5}[/tex]It seems you made error while writing option B, it should be - square root of 5.